Deuteron kinetic energy.

Concept.
According to the TORCHs requirement of the velocity of particles,
3He beta should be set to about 0.87. The FRS optical setting used in the November
test run was specified based on this requirement. Thus, we set the starting
point of the caclculation here.

3He beta in FRS beta=0.87000
T = 957.777 MeV/u
p = 4955.56588 MeV/c
K = 2887.63272 MeV
m = 2808.39222 MeV/c2

Energy loss in 12C 1.004 g (0.5507 cm, 1.8231341928 g/cm3)
deuteron p = 4944.55016 MeV/c -> dE=1.794011 MeV
3He p = 4955.56588 MeV/c -> dE= 7.867590 MeV
dE (average) = 4.83080050 MeV
At exit of (d,3He) reaction 
3He K = 2892.4635205 MeV
reaction mass product = mass(11B)+547.45=10252.5501 + 547.45
deuteron kinetic energy => 3450.4 MeV = 1713.2 MeV/u



I would prefer 3450 MeV (Albrecht said).


The momentum transfer vs. binding energy of eta

x axis: binding energy (MeV), y axis: momentum transfer (MeV/c)
proton beta with the same rigidity
TA-S20.93519
S2-S40.93382

--------------------------------------------------------------
Calculation log

kcvm31% k2m
input Kinetic Energy (MeV) [negative for MeV/nucleon]:3500
input Mass and Charge:2,1
 Apr. 2000
 mass of   1875.6134 is used
Kinetic Energy=      3500.00000 MeV
Momentum (P)  =      5037.78660 MeV/c
Rigidity (P/Z)=      5037.78660 MeV/c
beta          =         0.93716
gamma         =         2.86606
kcvm31% bc
bc 1.06
Copyright 1991-1994, 1997, 1998, 2000 Free Software Foundation, Inc.
This is free software with ABSOLUTELY NO WARRANTY.
For details type `warranty'.
957.777+(1.790065+7.867590)/2.0
961.777
scale=20
957.777+(1.790065+7.867590)/2.0
962.60582750000000000000


scale=10
3.01603*957.777+(1.790065+7.867590)/2.0
2893.5129928100

1694.5*2.01400
3412.723000

-------------d.in for start------------
30
4944.55016
c
35,1.8231341928
35
0.5507

-------------he.in for start------------
31
4955.56588
c
35,1.8231341928
35
0.5507